📌 How to Use
First read the questions carefully using the Read section. Use the Details button to understand concepts clearly. After completing reading, click Practice Quiz to test yourself.
📘 Study MCQs
Q1. A car accelerates uniformly from rest to 20 m/s in 5 seconds. What is its acceleration? Kinematics Basic
• 2 m/s²
• 4 m/s²
• 5 m/s²
• 8 m/s²
Answer: 4 m/s²
Step 1: Identify known values
Initial velocity, u = 0 m/s
Final velocity, v = 20 m/s
Time, t = 5 s
Step 2: Use the equation of motion
v = u + at
Step 3: Substitute values
20 = 0 + a × 5
Step 4: Solve for acceleration
a = 20/5 = 4 m/s²
Q2. A force of 10 N acts on a mass of 2 kg. What is the acceleration produced? Newton’s Laws
• 2 m/s²
• 5 m/s²
• 10 m/s²
• 20 m/s²
Answer: 5 m/s²
Step 1: Use Newton’s Second Law
F = ma
Step 2: Rearrange for acceleration
a = F/m
Step 3: Substitute values
a = 10 N / 2 kg = 5 m/s²
Q3. A body is dropped from a height of 80 m. How long does it take to reach the ground? (g = 10 m/s²) Free Fall
• 2 s
• 4 s
• 6 s
• 8 s
Answer: 4 s
Step 1: Use the equation for free fall
h = (1/2)gt²
Step 2: Rearrange for time
t = √(2h/g)
Step 3: Substitute values
t = √(2 × 80 / 10)
t = √(160/10) = √16 = 4 s
Q4. What is the work done when a force of 5 N moves an object through 2 m in the direction of force?
• 5 J
• 10 J
• 15 J
• 20 J
Answer: 10 J
Step 1: Use the work formula
Work = Force × Displacement × cosθ
Step 2: Since force and displacement are in same direction, θ = 0°
cos0° = 1
Step 3: Calculate
Work = 5 N × 2 m × 1 = 10 J
Q5. A current of 2 A flows through a resistor of 10 Ω. What is the power dissipated? Electricity
• 20 W
• 40 W
• 60 W
• 80 W
Answer: 40 W
Step 1: Use the power formula
P = I²R
Step 2: Substitute values
P = (2 A)² × 10 Ω
P = 4 × 10 = 40 W
Q6. A concave mirror has focal length 20 cm. Where should an object be placed to get a real image of magnification 2? Optics
• 30 cm
• 40 cm
• 50 cm
• 60 cm
Answer: 30 cm
Step 1: For real image, magnification m = -2 (negative for real image)
m = -v/u = -2 ⇒ v = 2u
Step 2: Mirror formula: 1/f = 1/v + 1/u
1/20 = 1/(2u) + 1/u
Step 3: Solve for u
1/20 = 1/(2u) + 2/(2u) = 3/(2u)
2u = 60 ⇒ u = 30 cm
Q7. What is the pressure at depth 10 m in water? (Density = 1000 kg/m³, g = 10 m/s²)
• 10⁴ Pa
• 10⁵ Pa
• 2×10⁴ Pa
• 2×10⁵ Pa
Answer: 10⁵ Pa
Step 1: Use pressure formula
P = hρg
Step 2: Substitute values
P = 10 m × 1000 kg/m³ × 10 m/s²
P = 100,000 Pa = 10⁵ Pa
Q8. A body of mass 5 kg is lifted to height 4 m. What is the potential energy gained? (g = 10 m/s²) Energy
• 100 J
• 200 J
• 300 J
• 400 J
Answer: 200 J
Step 1: Use potential energy formula
PE = mgh
Step 2: Substitute values
PE = 5 kg × 10 m/s² × 4 m
PE = 200 J
Q9. A wave has frequency 50 Hz and wavelength 2 m. What is its speed? Waves
• 25 m/s
• 50 m/s
• 100 m/s
• 200 m/s
Answer: 100 m/s
Step 1: Use wave equation
v = fλ
Step 2: Substitute values
v = 50 Hz × 2 m
v = 100 m/s
Q10. What is the equivalent resistance of two 6 Ω resistors in parallel?
• 2 Ω
• 3 Ω
• 4 Ω
• 5 Ω
Answer: 3 Ω
Step 1: For parallel combination
1/R = 1/R₁ + 1/R₂
Step 2: Substitute values
1/R = 1/6 + 1/6 = 2/6 = 1/3
Step 3: Therefore, R = 3 Ω
Q11. A ball is thrown vertically upward with velocity 20 m/s. How high does it rise? (g = 10 m/s²) Projectile
• 10 m
• 15 m
• 20 m
• 25 m
Answer: 20 m
Step 1: At maximum height, final velocity v = 0
Use equation: v² = u² – 2gh
Step 2: Rearrange for height
h = (u² – v²)/(2g)
Step 3: Substitute values
h = (20² – 0²)/(2×10)
h = 400/20 = 20 m
Q12. A heater is rated 1000 W, 220 V. What is its resistance?
• 48.4 Ω
• 50 Ω
• 100 Ω
• 220 Ω
Answer: 48.4 Ω
Step 1: Use power formula P = V²/R
Step 2: Rearrange for resistance
R = V²/P
Step 3: Substitute values
R = (220)²/1000 = 48400/1000 = 48.4 Ω
Q13. A body of volume 0.1 m³ is completely immersed in water. What is the buoyant force? (Density of water = 1000 kg/m³, g = 10 m/s²)
• 100 N
• 500 N
• 1000 N
• 2000 N
Answer: 1000 N
Step 1: Use Archimedes’ principle
Buoyant force = Weight of displaced liquid = Vρg
Step 2: Substitute values
F = 0.1 m³ × 1000 kg/m³ × 10 m/s²
F = 1000 N
Q14. A lens has power +5 D. What is its focal length? Optics
• 0.2 m
• 0.5 m
• 1 m
• 2 m
Answer: 0.2 m
Step 1: Use power formula
P = 1/f (in meters)
Step 2: Rearrange for focal length
f = 1/P
Step 3: Substitute values
f = 1/5 = 0.2 m = 20 cm
Q15. A car moves with speed 72 km/h. What is its speed in m/s?
• 10 m/s
• 15 m/s
• 20 m/s
• 25 m/s
Answer: 20 m/s
Step 1: Convert km/h to m/s
1 km/h = 1000 m/3600 s = 5/18 m/s
Step 2: Multiply by conversion factor
72 × (5/18) = (72×5)/18 = 360/18 = 20 m/s
Q16. What is the kinetic energy of a 2 kg mass moving at 10 m/s? Energy
• 50 J
• 100 J
• 150 J
• 200 J
Answer: 100 J
Step 1: Use kinetic energy formula
KE = (1/2)mv²
Step 2: Substitute values
KE = (1/2) × 2 kg × (10 m/s)²
KE = 1 × 100 = 100 J
Q17. A train accelerates from 10 m/s to 30 m/s in 10 s. What is its acceleration?
• 1 m/s²
• 2 m/s²
• 3 m/s²
• 4 m/s²
Answer: 2 m/s²
Step 1: Use acceleration formula
a = (v – u)/t
Step 2: Substitute values
a = (30 – 10)/10 = 20/10 = 2 m/s²
Q18. What is the current flowing through a 12 V battery connected to a 4 Ω resistor? Ohm’s Law
• 1 A
• 2 A
• 3 A
• 4 A
Answer: 3 A
Step 1: Use Ohm’s Law
V = IR
Step 2: Rearrange for current
I = V/R
Step 3: Substitute values
I = 12 V / 4 Ω = 3 A
Q19. A body moves 30 m East, then 40 m North. What is the displacement? Vectors
• 30 m
• 40 m
• 50 m
• 70 m
Answer: 50 m
Step 1: The displacements are perpendicular
East displacement = 30 m
North displacement = 40 m
Step 2: Use Pythagorean theorem
Resultant displacement = √(30² + 40²)
= √(900 + 1600) = √2500 = 50 m
Q20. What is the momentum of a 5 kg object moving at 4 m/s?
• 10 kg·m/s
• 15 kg·m/s
• 20 kg·m/s
• 25 kg·m/s
Answer: 20 kg·m/s
Step 1: Use momentum formula
p = mv
Step 2: Substitute values
p = 5 kg × 4 m/s = 20 kg·m/s
Q21. A sound wave travels 680 m in 2 s. What is its speed? Sound Waves
• 340 m/s
• 360 m/s
• 380 m/s
• 400 m/s
Answer: 340 m/s
Step 1: Use speed formula
Speed = Distance/Time
Step 2: Substitute values
v = 680 m / 2 s = 340 m/s
Q22. A force of 50 N acts on area 2 m². What is the pressure?
• 10 Pa
• 25 Pa
• 50 Pa
• 100 Pa
Answer: 25 Pa
Step 1: Use pressure formula
Pressure = Force/Area
Step 2: Substitute values
P = 50 N / 2 m² = 25 Pa
Q23. What is the time period of a pendulum with length 1 m? (g = 10 m/s²)
• 1 s
• 1.5 s
• 2 s
• 2.5 s
Answer: 2 s
Step 1: Use pendulum formula
T = 2π√(L/g)
Step 2: Substitute values
T = 2π√(1/10) = 2π√0.1
T ≈ 2 × 3.14 × 0.316 ≈ 2 s
Q24. A 100 W bulb operates for 5 hours. How much electrical energy is consumed? Electricity
• 0.5 kWh
• 1 kWh
• 1.5 kWh
• 2 kWh
Answer: 0.5 kWh
Step 1: Convert power to kW
100 W = 0.1 kW
Step 2: Energy = Power × Time
E = 0.1 kW × 5 h = 0.5 kWh
Q25. A body has weight 60 N on Earth. What is its mass? (g = 10 m/s²)
• 3 kg
• 6 kg
• 10 kg
• 60 kg
Answer: 6 kg
Step 1: Use weight formula
Weight = mg
Step 2: Rearrange for mass
m = W/g
Step 3: Substitute values
m = 60 N / 10 m/s² = 6 kg
Q26. What is the refractive index of water if light speed in water is 2.25×10⁸ m/s? (c = 3×10⁸ m/s) Optics
• 1.33
• 1.50
• 1.75
• 2.00
Answer: 1.33
Step 1: Refractive index formula
n = c/v
Step 2: Substitute values
n = (3×10⁸)/(2.25×10⁸) = 3/2.25 = 1.33
Q27. A spring extends by 5 cm under a load of 10 N. What is its spring constant? Elasticity
• 100 N/m
• 150 N/m
• 200 N/m
• 250 N/m
Answer: 200 N/m
Step 1: Use Hooke’s Law
F = kx
Step 2: Rearrange for spring constant
k = F/x
Step 3: Convert cm to m and substitute
x = 5 cm = 0.05 m
k = 10 N / 0.05 m = 200 N/m
Q28. A block slides down a frictionless inclined plane at angle 30°. What is its acceleration? (g = 10 m/s²) Inclined Plane
• 2.5 m/s²
• 5 m/s²
• 7.5 m/s²
• 10 m/s²
Answer: 5 m/s²
Step 1: Acceleration down inclined plane
a = g sinθ
Step 2: Substitute values
a = 10 × sin30° = 10 × 0.5 = 5 m/s²
Q29. Q = 84000 J Calorimetry
• 4200 J
• 8400 J
• 42000 J
• 84000 J
Answer: 84000 J
Step 1: Use heat formula
Q30. A convex lens forms a real image at 30 cm when object is at 20 cm. What is its focal length?
• 10 cm
• 12 cm
• 15 cm
• 20 cm
Answer: 12 cm
Step 1: Use lens formula
1/f = 1/v – 1/u
Step 2: For real image, v is positive, u is negative
u = -20 cm, v = +30 cm
Step 3: Substitute values
1/f = 1/30 – (-1/20) = 1/30 + 1/20
1/f = (2 + 3)/60 = 5/60 = 1/12
f = 12 cm