📘 Study MCQs
Q1. In the sign convention for spherical mirrors, distances are measured from the __________.
A. Centre of curvature
B. Focus
C. Pole
D. Object
C. PoleIn the Cartesian sign convention commonly used for spherical mirrors, all distances are measured from the pole (P), which is the geometric center of the mirror’s reflecting surface. The pole serves as the reference point or origin for coordinate measurements. Distances measured in the direction of incident light are taken as positive, while those measured opposite to the incident light are negative. The centre of curvature, focus, and object positions are all specified relative to this reference point.
Q2. According to the sign convention, distances measured in the direction of the incident light are taken as __________.
A. Positive
B. Negative
C. Zero
D. Infinite
A. PositiveIn the standard Cartesian sign convention used in optics, distances measured in the direction of the incident light (from the pole toward the object side) are considered positive. Conversely, distances measured opposite to the direction of incident light are taken as negative. This convention ensures consistency when applying the mirror formula and calculating magnification, particularly when dealing with real and virtual images.
Q3. For a spherical mirror, the focal length (f) and object distance (u) are both negative. What type of mirror is it?
A. Convex mirror
B. Concave mirror
C. Plane mirror
D. Cannot determine
B. Concave mirrorAccording to the Cartesian sign convention, concave mirrors have their focus in front of the mirror, in the direction of incident light. Since distances in the direction of incident light are taken as positive, the focal length of a concave mirror is actually negative under the standard convention (where the incident light direction is from object to mirror). When both u and f are negative, it indicates a concave mirror. For convex mirrors, the focal length is positive (focus behind the mirror), while object distance u is typically negative.
Q4. The mirror formula is __________.
A. 1/v + 1/u = 1/f
B. 1/v – 1/u = 1/f
C. uv = f
D. u + v = f
A. 1/v + 1/u = 1/fThe mirror formula relates the object distance (u), image distance (v), and focal length (f) of a spherical mirror. It is expressed as 1/u + 1/v = 1/f. When using the Cartesian sign convention, this formula works for both concave and convex mirrors, with the appropriate sign conventions for u, v, and f. The formula is derived from the geometry of reflection and is fundamental for calculating image positions.
Q5. Magnification (m) for a mirror is the ratio of the height of the image to the __________.
A. Height of the object
B. Focal length
C. Object distance
D. Radius of curvature
A. Height of the objectMagnification (m) for a mirror is defined as the ratio of the image height (hᵢ) to the object height (hₒ). It indicates how many times larger or smaller the image is compared to the object. Mathematically, m = hᵢ/hₒ. A positive magnification indicates an erect image (virtual), while a negative magnification indicates an inverted image (real). Magnification can also be expressed in terms of distances as m = -v/u.
Q6. Magnification can also be calculated using the formula m = __________.
A. -v/u
B. v/u
C. u/v
D. -f/u
A. -v/uMagnification for a mirror is also given by m = -v/u, where v is the image distance and u is the object distance. The negative sign is included to account for the sign convention: when v and u are both negative (as is typical for real objects in front of concave mirrors), the ratio yields the correct sign for the image orientation. This formula is derived from similar triangles in ray diagrams and provides a convenient way to calculate magnification without knowing image or object heights.
Q7. A positive magnification value indicates that the image is __________.
A. Real
B. Inverted
C. Virtual and erect
D. Diminished
C. Virtual and erectA positive magnification (m > 0) indicates that the image is erect (upright) relative to the object. For mirrors, an erect image is always virtual, meaning it is formed behind the mirror and cannot be projected on a screen. Conversely, a negative magnification (m < 0) indicates an inverted image, which for mirrors is real and formed in front of the mirror. The magnitude of m indicates whether the image is enlarged (|m| > 1), diminished (|m| < 1), or same size (|m| = 1).
Q8. The bending of light as it passes from one medium to another is called __________.
A. Reflection
B. Dispersion
C. Refraction
D. Scattering
C. RefractionRefraction is the phenomenon in which light changes direction when it passes obliquely from one transparent medium to another, due to a change in its speed. This bending occurs at the interface between the two media. Reflection involves light bouncing back from a surface, dispersion is the splitting of light into colors, and scattering is the irregular diffusion of light in multiple directions.
Q9. The Refractive Index is the ratio of the speed of light in vacuum to the speed of light in __________.
A. Air
B. Water
C. The medium
D. Glass
C. The mediumThe absolute refractive index (n) of a medium is defined as n = c/v, where c is the speed of light in vacuum (approximately 3 × 10⁸ m/s) and v is the speed of light in that medium. It quantifies how much the medium slows down light compared to vacuum. Since the speed of light in any material medium is always less than or equal to c, the refractive index is always ≥ 1.
Q10. Which medium has the highest refractive index among the given options?
A. Water
B. Crown glass
C. Diamond
D. Alcohol
C. DiamondDiamond has the highest refractive index among common materials, typically around 2.42. This high refractive index results in diamond’s exceptional brilliance and sparkle, as it causes significant bending of light and total internal reflection. For comparison, water has n ≈ 1.33, crown glass n ≈ 1.52, and alcohol (ethanol) n ≈ 1.36. Diamond’s high refractive index is due to its dense atomic structure and strong interaction with light.
Q11. Which medium has the lowest refractive index among the given common materials?
A. Air
B. Water
C. Kerosene
D. Ice
A. AirAir has the lowest refractive index among the given options, approximately 1.0003. This is very close to that of vacuum (n = 1.00). Water has n ≈ 1.33, ice has n ≈ 1.31, and kerosene has n ≈ 1.44. The low refractive index of air is because it is a gas with low density, allowing light to travel through it at nearly its vacuum speed.
Q12. A transparent material with a curved surface, used to converge or diverge light, is called a __________.
A. Mirror
B. Prism
C. Lens
D. Glass slab
C. LensA lens is a transparent optical component with curved surfaces that refracts light to converge or diverge rays. Lenses are typically made of glass or plastic and work on the principle of refraction. Mirrors work by reflection, prisms disperse light through refraction, and glass slabs shift light laterally without significant convergence or divergence.
Q13. A lens that is thicker in the middle and thinner at the edges is a __________ lens.
A. Concave
B. Convex
C. Plano-concave
D. Biconcave
B. ConvexA convex lens (also called a converging lens) is thicker at the center than at the edges. This shape causes parallel light rays to converge to a focal point after refraction. In contrast, concave lenses are thinner at the center and thicker at the edges, causing light rays to diverge. Convex lenses are used in applications like magnifying glasses, cameras, and corrective lenses for farsightedness.
Q14. For a convex lens, a real and inverted image is formed when the object is placed __________.
A. Between the lens and its focus
B. At the focus
C. Beyond the focus
D. Anywhere
C. Beyond the focusA convex lens forms a real and inverted image only when the object is placed beyond the focus (F). When the object is placed between the lens and the focus, the image formed is virtual, erect, and magnified. When the object is exactly at the focus, the image is formed at infinity. The condition “beyond the focus” includes positions from just beyond F to infinity.
Q15. The formula that relates object distance (u), image distance (v), and focal length (f) for a lens is __________.
A. 1/v – 1/u = 1/f
B. 1/v + 1/u = 1/f
C. 1/u – 1/v = 1/f
D. uv = f
A. 1/v – 1/u = 1/fThe lens formula is 1/v – 1/u = 1/f, where u is the object distance, v is the image distance, and f is the focal length. This formula is derived from the geometry of refraction through lenses and applies to both convex and concave lenses when used with appropriate sign conventions. It differs from the mirror formula (1/u + 1/v = 1/f) due to the direction of light transmission through lenses.
Q16. The power of a lens is defined as the reciprocal of its __________.
A. Diameter
B. Focal length
C. Radius of curvature
D. Thickness
B. Focal lengthThe power (P) of a lens is defined as the reciprocal of its focal length (f) expressed in meters. Mathematically, P = 1/f (in meters). Power indicates the degree to which a lens converges or diverges light. A lens with a shorter focal length has greater power, meaning it bends light more strongly. The unit of power is the dioptre (D).
Q17. The unit of power of a lens is __________.
A. Meter
B. Centimeter
C. Dioptre
D. Joule
C. DioptreThe dioptre (D) is the SI unit of lens power. One dioptre is defined as the power of a lens with a focal length of one meter. Power is calculated as P = 1/f (where f is in meters). A convex lens has positive power (measured in positive dioptres), while a concave lens has negative power. For example, a lens with f = 0.5 m has power P = +2 D.
Q18. A convex lens has a __________ focal length and __________ power.
A. Positive, positive
B. Negative, negative
C. Positive, negative
D. Negative, positive
A. Positive, positiveAccording to the Cartesian sign convention, a convex lens has a positive focal length because its principal focus lies on the opposite side of the lens from the incident light. Since power is the reciprocal of focal length (P = 1/f), a positive focal length yields positive power. Convex lenses are converging lenses and are used to correct hypermetropia (farsightedness).
Q19. A concave lens always forms a __________ image.
A. Real, inverted, and diminished
B. Virtual, erect, and diminished
C. Real, erect, and magnified
D. Virtual, inverted, and magnified
B. Virtual, erect, and diminishedA concave lens (diverging lens) always produces an image that is virtual (cannot be projected on a screen), erect (upright), and diminished (smaller than the object), regardless of the object’s position. This is because the lens diverges all incident rays, and their extensions appear to converge at a point on the same side as the object. This property makes concave lenses suitable for correcting myopia.
Q20. Magnification for a lens is given by the formula m = __________.
A. v/u
B. u/v
C. -v/u
D. h_o / h_i
A. v/uFor a lens, magnification is given by m = v/u, where v is the image distance and u is the object distance. This differs from the mirror formula (m = -v/u) because of the different sign conventions and the fact that light passes through a lens rather than reflecting off it. The sign of m indicates image orientation: positive m indicates an erect image (virtual for lenses), negative m indicates an inverted image (real for lenses).
Q21. If the magnification produced by a lens is +2, the image is __________.
A. Real and inverted
B. Virtual and inverted
C. Virtual and erect
D. Real and erect
C. Virtual and erectFor a lens, a positive magnification indicates that the image is erect (upright) relative to the object. An erect image formed by a lens is always virtual, meaning it is formed on the same side of the lens as the object and cannot be projected onto a screen. The magnitude |m| = 2 indicates that the image is twice the size of the object (enlarged). This occurs when the object is placed between the lens and its focus for a convex lens.
Q22. Which type of lens is used to correct myopia (short-sightedness)?
A. Convex lens
B. Concave lens
C. Cylindrical lens
D. Bifocal lens
B. Concave lensMyopia (short-sightedness) is a condition where the eye focuses light in front of the retina, making distant objects appear blurry. A concave (diverging) lens is used to correct this condition by diverging incoming light rays slightly before they enter the eye. This shifts the focal point backward onto the retina. Convex lenses are used to correct hypermetropia (farsightedness), while cylindrical lenses correct astigmatism.
Q23. The refractive index of water is approximately __________.
A. 1.00
B. 1.33
C. 1.50
D. 2.42
B. 1.33The absolute refractive index of water is approximately 1.33. This means that the speed of light in water is about 1/1.33 ≈ 0.75 times its speed in vacuum (approximately 2.25 × 10⁸ m/s). This value can vary slightly with temperature, purity, and the wavelength of light, with 1.33 being the commonly cited standard at room temperature for visible light.
Q24. Light travels fastest in which medium?
A. Glass
B. Water
C. Vacuum
D. Diamond
C. VacuumLight travels fastest in vacuum, at approximately 3 × 10⁸ m/s. In any material medium, light interacts with atoms and molecules, causing it to slow down. Vacuum has no such particles, so light achieves its maximum possible speed. Among the options, glass, water, and diamond all have refractive indices greater than 1, meaning light travels slower in them than in vacuum.
Q25. According to the sign convention for lenses, the focal length of a convex lens is __________.
A. Positive
B. Negative
C. Zero
D. Infinite
A. PositiveAccording to the Cartesian sign convention, the focal length of a convex lens is taken as positive. This is because the principal focus of a convex lens lies on the opposite side of the lens from the incident light (the real focus). For a concave lens, the focus is virtual and located on the same side as the incident light, so its focal length is taken as negative.
Q26. A lens with a power of +4.0 D is a __________ lens.
A. Concave
B. Convex
C. Plane
D. Cannot say
B. ConvexPositive power indicates a convex (converging) lens. Power is defined as P = 1/f (with f in meters). A power of +4.0 D corresponds to a focal length of f = 1/P = 1/4 = 0.25 m = 25 cm. Since the power is positive, the lens is convex. Concave lenses have negative power. This lens would converge light and could be used to correct hypermetropia.
Q27. If the image distance (v) is positive for a lens, the image is formed on the __________ side.
A. Same as the object
B. Opposite to the object
C. On the lens itself
D. Cannot say
B. Opposite to the objectAccording to the sign convention for lenses, a positive image distance (v) indicates that the image is formed on the opposite side of the lens from the object (the side where the light emerges). For a convex lens, this typically corresponds to a real image. Conversely, a negative image distance indicates a virtual image formed on the same side as the object.
Q28. Which lens has a negative focal length?
A. Convex lens
B. Concave lens
C. Both
D. Neither
B. Concave lensA concave lens has a negative focal length according to the Cartesian sign convention. This is because its principal focus is virtual and located on the same side of the lens as the incident light. For a convex lens, the focus is real and lies on the opposite side, giving it a positive focal length. The negative focal length of concave lenses results in negative power as well.
Q29. When an object is placed at 2F (twice the focal length) of a convex lens, the image is formed __________.
A. At F
B. At 2F on the other side
C. At infinity
D. Between F and 2F
B. At 2F on the other sideWhen an object is placed at a distance of 2F (twice the focal length) from a convex lens, the image is formed at 2F on the opposite side of the lens. This image is real, inverted, and exactly the same size as the object. This is a specific case that can be verified using the lens formula 1/v – 1/u = 1/f, where u = -2f, giving v = 2f.
Q30. The refractive index of a medium depends on the __________ of light.
A. Intensity
B. Speed
C. Color (wavelength)
D. Source
B. SpeedRefractive index is fundamentally defined as n = c/v, so it directly depends on the speed of light in the medium. However, the speed itself varies with the wavelength (color) of light due to dispersion. Therefore, refractive index also depends on the color (wavelength) of light. For a given medium, blue light (shorter wavelength) has a higher refractive index than red light (longer wavelength).
Q31. Which of the following has a refractive index greater than 1.5?
A. Water
B. Crown glass
C. Dense flint glass
D. Alcohol
C. Dense flint glassDense flint glass has a refractive index typically ranging from about 1.65 to 1.70, which is greater than 1.5. Crown glass has a refractive index around 1.52, slightly above 1.5. Water (≈1.33) and alcohol (≈1.36) have refractive indices well below 1.5. Dense flint glass contains lead oxide, which increases its optical density and dispersion properties.
Q32. Snell’s Law relates the angles of incidence and refraction with the __________.
A. Focal length
B. Refractive indices
C. Object distance
D. Image distance
B. Refractive indicesSnell’s law states that n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the two media, and θ₁ and θ₂ are the angles of incidence and refraction, respectively. Thus, it relates the angles to the refractive indices of the media. This law is fundamental to understanding refraction and is used to calculate how light bends when passing between different media.
Q33. A lens forms an image that is four times the size of the object. The magnification is __________.
A. 4
B. 1/4
C. -4
D. -1/4
A. 4Magnification (m) is defined as the ratio of the image size to the object size. If the image is four times the size of the object, the absolute value of magnification is 4. Without additional information about whether the image is erect or inverted, the magnification could be either +4 (if virtual and erect) or -4 (if real and inverted). Since the question does not specify orientation, the magnitude 4 is the correct answer from the given options.
Q34. The power of a lens with a focal length of 0.5 meters is __________.
A. 0.5 D
B. 1 D
C. 2 D
D. 4 D
C. 2 DPower of a lens is given by P = 1/f, where f is the focal length in meters. For f = 0.5 m, P = 1/0.5 = 2 dioptres (D). The sign of the power depends on the type of lens: a convex lens would have +2 D, while a concave lens would have -2 D. Since the sign is not specified, the magnitude 2 D is the correct numerical answer.
Q35. A concave lens is also called a __________ lens.
A. Converging
B. Diverging
C. Magnifying
D. Focusing
B. DivergingA concave lens is called a diverging lens because it causes parallel incident light rays to spread out (diverge) after refraction. The extensions of these diverging rays appear to originate from a virtual focus on the same side as the incident light. In contrast, a convex lens is called a converging lens because it brings parallel rays together at a real focus.
Q36. For a lens, if the object distance (u) is negative, it means the object is __________.
A. Virtual
B. On the same side as incident light
C. Real and placed on the opposite side
D. Always real
C. Real and placed on the opposite sideAccording to the Cartesian sign convention for lenses, the object distance (u) is taken as negative when the object is real and placed on the side from which light is coming (the incident light side). A positive object distance would indicate a virtual object (where converging rays are incident on the lens). In standard lens problems, objects are typically real, so u is negative.
Q37. Which of these materials is likely to bend light the most?
A. Air (n=1.0003)
B. Water (n=1.33)
C. Glass (n~1.5)
D. Diamond (n=2.42)
DiamondDiamond has the highest refractive index (approximately 2.42) among the given options. The degree to which light bends when entering a medium is determined by the change in speed, which is quantified by the refractive index. A higher refractive index means a greater change in speed and thus more bending. Diamond’s high refractive index is responsible for its exceptional brilliance and sparkle.
Q38. The image formed by a convex lens is virtual and erect when the object is placed __________.
A. At 2F
B. Beyond 2F
C. At F
D. Between the lens and F
D. Between the lens and FA convex lens forms a virtual, erect, and magnified image only when the object is placed between the lens and its focus (F). In this position, the refracted rays diverge, and their extensions meet on the same side as the object, forming a virtual image. This principle is used in simple magnifiers and magnifying glasses. For all other positions (beyond F), the image formed is real and inverted.
Q39. Two lenses of power +2.0 D and -0.5 D are placed in contact. The combined power is __________.
A. +1.5 D
B. +2.5 D
C. -1.5 D
D. +0.5 D
A. +1.5 DWhen lenses are placed in contact, the total power is the algebraic sum of their individual powers. Therefore, P_total = P₁ + P₂ = (+2.0 D) + (-0.5 D) = +1.5 D. The combined focal length can be found from f_total = 1/P_total = 1/1.5 ≈ 0.667 m. This principle is used in designing compound lenses and corrective eyewear.
Q40. The principal focus of a concave lens is __________.
A. Real
B. Virtual
C. Positive
D. On the same side as the object
B. VirtualThe principal focus of a concave lens is virtual. This is because parallel rays incident on a concave lens diverge after refraction, and their extensions appear to converge at a point on the same side of the lens as the incident light. Since light rays do not actually pass through this point, it is called a virtual focus. In contrast, convex lenses have a real focus on the opposite side.
Q41. The lens formula, 1/v – 1/u = 1/f, is applicable to __________.
A. Only convex lenses
B. Only concave lenses
C. Both convex and concave lenses
D. Only spherical mirrors
C. Both convex and concave lensesThe lens formula 1/v – 1/u = 1/f is applicable to both convex and concave lenses when used with the appropriate sign conventions. For convex lenses, f is positive; for concave lenses, f is negative. The formula holds for all thin lenses and is derived from the geometry of refraction. It is a fundamental equation in geometric optics for calculating image distances and focal lengths.
Q42. If the magnification is less than 1 (|m| < 1), the image is __________.
A. Enlarged
B. Same size
C. Diminished
D. Inverted
C. DiminishedMagnification (m) is the ratio of image size to object size. When |m| < 1, the image is smaller than the object, meaning it is diminished. Conversely, |m| > 1 indicates an enlarged image, and |m| = 1 indicates an image of the same size. The sign of m (positive or negative) indicates orientation (erect or inverted), not size.
Q43. Which lens is used as a simple microscope (magnifying glass)?
A. Concave lens
B. Convex lens of short focal length
C. Convex lens of long focal length
D. Concave mirror
B. Convex lens of short focal lengthA simple microscope, commonly called a magnifying glass, uses a convex lens with a short focal length. When an object is placed between the lens and its focus, it produces a virtual, erect, and magnified image. A shorter focal length allows for greater magnification. Concave lenses produce diminished images and are not suitable for magnification purposes.
Q44. The speed of light in a medium with refractive index 1.5 is __________.
A. 2 x 10⁸ m/s
B. 3 x 10⁸ m/s
C. 4.5 x 10⁸ m/s
D. 1.5 x 10⁸ m/s
A. 2 x 10⁸ m/sThe speed of light in a medium is given by v = c/n, where c = 3 × 10⁸ m/s (speed in vacuum) and n is the refractive index. For n = 1.5, v = (3 × 10⁸)/1.5 = 2 × 10⁸ m/s. This is the approximate speed of light in materials like crown glass. The reduction in speed causes the bending of light when it enters the medium from vacuum or air.
Q45. A real image formed by a lens can be obtained on a __________.
A. Mirror
B. Lens itself
C. Screen
D. It cannot be obtained
C. ScreenA real image is formed when light rays actually converge at a point after passing through the lens. Since the rays physically meet at that location, a screen placed at that point can capture and display the image. This property distinguishes real images from virtual images, which are formed where rays only appear to diverge from and cannot be projected on a screen.
Q46. The refractive index of a medium is always __________.
A. Less than 1
B. Equal to 1
C. Greater than 1
D. Greater than or equal to 1
D. Greater than or equal to 1The absolute refractive index n = c/v, where c is the speed of light in vacuum (approximately 3 × 10⁸ m/s) and v is the speed in the medium. Since light travels slower in any material medium than in vacuum (v ≤ c), the ratio c/v is always greater than or equal to 1. The only medium with n = 1 is vacuum itself. All other media have n > 1.
Q47. When light enters a denser medium from a rarer medium, it bends __________ the normal.
A. Away from
B. Towards
C. Parallel to
D. Does not bend
B. TowardsWhen light travels from a rarer (optically less dense) medium to a denser (optically more dense) medium, its speed decreases, causing it to bend toward the normal. The angle of refraction becomes smaller than the angle of incidence. For example, when light enters water from air, it bends toward the normal. Conversely, when light enters a rarer medium from a denser medium, it bends away from the normal.
Q48. A lens of power -2.0 D is a __________ lens of focal length __________ m.
A. Convex, +0.5
B. Concave, -0.5
C. Convex, -0.5
D. Concave, +0.5
B. Concave, -0.5A negative power indicates a concave (diverging) lens. Power is related to focal length by P = 1/f (where f is in meters). For P = -2.0 D, the focal length f = 1/P = 1/(-2.0) = -0.5 m. The negative sign confirms it is a concave lens. Concave lenses have negative focal lengths and are used to correct myopia (short-sightedness).
Q49. Which of these statements about magnification is true?
A. It has a unit.
B. It is always positive.
C. It is the ratio of image distance to object distance for lenses.
D. It is always greater than 1.
C. It is the ratio of image distance to object distance for lenses.For lenses, magnification is given by m = v/u, where v is the image distance and u is the object distance. This is a true statement. Magnification is dimensionless (has no unit), can be positive or negative depending on whether the image is erect or inverted, and can be less than, equal to, or greater than 1 depending on whether the image is diminished, same size, or enlarged.
Q50. For a convex lens, if the object is placed at the focus (F), the image is formed at __________.
A. F
B. 2F
C. Infinity
D. Between F and 2F
C. InfinityWhen an object is placed exactly at the focus (F) of a convex lens, the refracted rays emerge parallel to each other. Since parallel rays never converge, the image is said to be formed at infinity. This principle is used in devices like searchlights and projectors, where a light source placed at the focus produces a parallel beam of light.
