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Q1. The formula to calculate time taken when distance and speed are known is:
Time = Distance ÷ Speed. This is the correct formula derived from the speed formula: Speed = Distance/Time. The other options are incorrect: multiplying distance and speed gives distance×speed (not time), speed/distance is the reciprocal, and adding is meaningless.
Q2. An odometer in a vehicle measures:
An odometer measures the total distance travelled by a vehicle. A speedometer measures instantaneous speed. Time and fuel are measured by other devices. The odometer shows the cumulative distance in kilometres.
Q3. A car travels at a speed of 40 kilometre per hour. How much time will it take to cover 120 kilometre?
Time = Distance ÷ Speed = 120 km ÷ 40 km/h = 3 hours. 2 hours would be for 80 km, 4 hours for 160 km, and 5 hours for 200 km. The correct answer is 3 hours.
Q4. If a cyclist covers 60 kilometre in 3 hour, the speed is:
Speed = Distance ÷ Time = 60 km ÷ 3 h = 20 km/h. 30 km/h would be 90 km in 3 h, 180 km/h is 60×3, and 63 km/h is 60+3. The correct answer is 20 km/h.
Q5. A bar graph is used to represent data:
A bar graph represents data using rectangular bars of equal width. Pictures are used in pictographs, circles in pie charts, and lines in line graphs. The bars in a bar graph have equal width for fair comparison.
Q6. In a distance-time graph, time is usually plotted on which axis?
In a distance-time graph, time is plotted on the x-axis (horizontal) and distance is plotted on the y-axis (vertical). This is the standard convention. The z-axis is not used in 2D graphs.
Q7. A straight line sloping upward on a distance-time graph represents:
A straight line sloping upward on a distance-time graph means equal distances are covered in equal time intervals, indicating uniform motion. A horizontal line means at rest, and a curved line means non-uniform motion.
Q8. A horizontal line (parallel to time axis) on a distance-time graph means:
A horizontal line on a distance-time graph means the distance is not changing with time, so the object is at rest. A sloping line indicates motion, and oscillation would be a curved pattern.
Q9. The slope of a distance-time graph gives:
The slope (rise/run) of a distance-time graph gives the speed of the object. A steeper slope means greater speed. A horizontal line (zero slope) means zero speed (at rest). It does not give time, distance itself, or acceleration.
Q10. A curved line on a distance-time graph indicates:
A curved line on a distance-time graph indicates non-uniform motion because the speed is changing. Uniform motion is a straight line, rest is horizontal, and no motion is also horizontal. The curve shows varying speed.
Q11. One complete to-and-fro motion of a pendulum bob is called:
One complete to-and-fro motion of a pendulum bob is called one oscillation. It is also called one vibration. Rotation and revolution refer to circular motion. Oscillation is the correct term for pendulum motion.
Q12. The time taken to complete one oscillation is called:
The time taken to complete one oscillation is the time period. Frequency is the number of oscillations per second, amplitude is maximum displacement, and speed is distance per time. Time period is the correct term.
Q13. If a pendulum completes 30 oscillations in 60 second, its time period is:
Time period = Total time ÷ Number of oscillations = 60 s ÷ 30 = 2 seconds. 0.5 s would be 30/60 (frequency), 30 s is the number, and 1800 s is 60×30. The correct answer is 2 seconds.
Q14. Which of the following is an example of uniform motion?
Uniform motion means constant speed in a straight line. A train starting from a station accelerates, a ball falling accelerates, and a bicycle stopping decelerates. Only a car with constant speed is uniform motion.
Q15. Which of the following is an example of non-uniform motion?
Non-uniform motion means changing speed or direction. A car accelerating has changing speed, so it is non-uniform. A fan at constant speed is uniform, a planet in circular orbit has constant speed but changing direction (uniform circular motion), and a pendulum at constant period is uniform oscillatory motion.
Q16. A bus covers first 50 kilometre in 1 hour and next 50 kilometre in 1.5 hour. This motion is:
The bus covers equal distances (50 km) in unequal times (1 h and 1.5 h), so the speed is not constant. This is non-uniform motion. Uniform motion would require equal times for equal distances.
Q17. A distance-time graph for an object moving with uniform speed is:
Uniform speed means equal distances in equal time, so the distance-time graph is a straight line sloping upward. A curved line indicates non-uniform speed, a horizontal line indicates rest, and a vertical line is not possible for a distance-time graph.
Q18. A distance-time graph for an object at rest is:
For an object at rest, distance does not change with time, so the graph is a horizontal line parallel to the time axis. Sloping lines indicate motion, and curved lines indicate non-uniform motion.
Q19. To find the speed of an object from a distance-time graph, we calculate:
Speed is the slope (rise/run) of a distance-time graph. The area under the graph gives distance in a speed-time graph, intercept gives initial position, and length is not used. The slope gives speed.
Q20. An odometer reads 1200 kilometre at the start of a journey and 1500 kilometre at the end. The distance travelled is:
Distance travelled = Final reading – Initial reading = 1500 – 1200 = 300 km. 2700 km is the sum, 1500 km is final, and 1200 km is initial. The correct distance is 300 km.
Q21. A car travels at a speed of 15 metre per second. How much time will it take to cover 300 metre?
Time = Distance ÷ Speed = 300 m ÷ 15 m/s = 20 seconds. 0.05 s is 15/300, 4500 s is 300×15, and 315 s is 300+15. The correct answer is 20 seconds.
Q22. A train covers 360 kilometre in 4 hour. What is its speed?
Speed = Distance ÷ Time = 360 km ÷ 4 h = 90 km/h. 1440 km/h is 360×4, 364 is 360+4, and 90 m/s would be 324 km/h. The correct answer is 90 km/h.
Q23. A bar graph is most suitable for showing:
Bar graphs are best for comparing different categories (like distances of different vehicles). Change over time is better shown by line graphs, pendulum path by diagrams, and distance-time graphs for motion. Bar graphs compare quantities.
Q24. In a bar graph, the width of all bars should be:
In a bar graph, all bars should have equal width to ensure fair comparison. The height of the bars represents the value being compared. Varying widths would make the graph misleading.
Q25. On a distance-time graph, if the line becomes steeper, it means:
A steeper slope on a distance-time graph means the object is covering more distance in the same time, so the speed is increasing. Decreasing steepness means speed is decreasing, a horizontal line means rest, and a downward slope means moving backwards.
Q26. On a distance-time graph, if the line becomes less steep, it means:
A less steep slope means the object is covering less distance in the same time, so the speed is decreasing. Increasing steepness means speed increasing, horizontal means rest, and downward means moving backwards.
Q27. The number of oscillations per second is called:
Frequency is the number of oscillations per second, measured in hertz (Hz). Time period is the time for one oscillation, amplitude is maximum displacement, and speed is distance per time. Frequency is the correct term.
Q28. If the frequency of a pendulum is 2 hertz, its time period is:
Time period = 1 / Frequency = 1/2 = 0.5 seconds. 2 seconds is the frequency as time, 4 seconds is 2×2, and 1 second is if frequency were 1 Hz. The correct answer is 0.5 seconds.
Q29. A distance-time graph for non-uniform motion is:
Non-uniform motion (changing speed) is represented by a curved line on a distance-time graph. A straight line indicates uniform motion, a horizontal line indicates rest, and a vertical line is not used.
Q30. A person walks 10 metre in 2 second, then 20 metre in 4 second, then 30 metre in 6 second. This motion is:
Speed is constant: 10/2 = 5 m/s, 20/4 = 5 m/s, 30/6 = 5 m/s. Since equal distances are covered in equal time intervals, the motion is uniform. Non-uniform would have different speeds.
Q31. A girl covers 100 metre in 20 second, then 100 metre in 30 second. Her average speed for the whole journey is:
Average speed = Total distance / Total time = (100+100) / (20+30) = 200 / 50 = 4 m/s. 5 m/s is 100/20, 6 m/s is not, and 10 m/s is 200/20. The average is 4 m/s.
Q32. The slope of a distance-time graph for an object at rest is:
For an object at rest, distance does not change with time, so the slope (change in distance/change in time) is zero. A positive slope means motion, infinite slope would be a vertical line (not possible), and negative would mean moving backwards.
Q33. A car moves with a speed of 25 metre per second. How much distance will it cover in 40 second?
Distance = Speed × Time = 25 m/s × 40 s = 1000 m. 1.6 m is 40/25, 65 m is 25+40, and 15 m is 40-25. The correct distance is 1000 m.
Q34. The odometer of a car reads 2000 kilometre at 10:00 AM and 2400 kilometre at 11:00 AM. The average speed of the car in this time is:
Distance = 2400 – 2000 = 400 km. Time = 1 hour. Speed = 400/1 = 400 km/h. 200 km/h would be half, 40 km/h is 400/10, and 4000 km/h is 400×10. The correct speed is 400 km/h.
Q35. Which of the following is NOT shown by a distance-time graph?
A distance-time graph shows motion characteristics: rest, uniform/non-uniform motion, and speed. It does not show the colour, shape, or any physical property of the object other than its motion.
Q36. A bus travels at 30 kilometre per hour. How long will it take to cover 15 kilometre?
Time = Distance ÷ Speed = 15 km ÷ 30 km/h = 0.5 hour (30 minutes). 2 hours would be for 60 km, 450 hours is 15×30, and 30 hours is distance×speed? The correct answer is 0.5 hour.
Q37. The motion of a simple pendulum is:
A simple pendulum moves back and forth in a regular pattern, which is oscillatory motion. It is not uniform (speed changes), not rectilinear (straight line), and not circular. Oscillatory motion is the correct classification.
Q38. On a distance-time graph, a straight line sloping downward would indicate:
A downward slope means distance is decreasing with time, so the object is moving back towards the starting point. Forward motion has positive slope, rest is horizontal, and increasing speed is a curve.
Q39. To compare the distances covered by five different animals in one hour, the best graph is:
A bar graph is best for comparing different categories (animals) on a single measure (distance). A line graph is for change over time, a pie chart for parts of a whole, and a distance-time graph for motion of one object. Bar graph is the correct choice.
Q40. A man runs 200 metre in 25 second, then stops for 10 second, then runs another 100 metre in 20 second. The motion is:
The man has different speeds (200/25 = 8 m/s, 0 m/s while stopped, 100/20 = 5 m/s). Since speed changes and he also stops, the motion is non-uniform. It is not uniform, circular, or oscillatory.
Q41. The formula relating speed, distance and time is:
The correct formula is Speed = Distance ÷ Time. Distance × Time is not correct, Time = Speed × Distance is incorrect, and Distance = Time/Speed is also incorrect. Speed is distance per unit time.
Q42. A car moves with uniform speed and covers 240 metre in 12 second. Its speed is:
Speed = Distance ÷ Time = 240 m ÷ 12 s = 20 m/s. 2880 m/s is 240×12, 0.05 m/s is 12/240, and 252 m/s is 240+12. The correct speed is 20 m/s.
Q43. The time taken to complete 10 oscillations of a pendulum is 25 second. The time period is:
Time period = Total time ÷ Number of oscillations = 25 s ÷ 10 = 2.5 s. 0.4 s is 10/25 (frequency), 250 s is 25×10, and 35 s is 25+10. The correct answer is 2.5 seconds.
Q44. A distance-time graph helps us to:
A distance-time graph shows how distance changes with time, so we can find the speed (slope) at any point. It does not show colour, weight, or temperature. The graph is only for motion information.
Q45. If an object covers 50 metre in first 5 second, 100 metre in next 5 second, and 150 metre in next 5 second, the motion is:
The distances are increasing (50, 100, 150) in equal time intervals (5 s). The speed is increasing, so the motion is non-uniform (accelerated). Uniform would have equal distances in equal time.
Q46. A train travels at 108 kilometre per hour. Its speed in metre per second is:
To convert km/h to m/s, multiply by 5/18 (or divide by 3.6). 108 × 5/18 = 30 m/s. 388.8 is 108×3.6, 10.8 is 108/10, and 108 is km/h not m/s. The correct answer is 30 m/s.
Q47. The device that measures the speed of a vehicle at any instant is:
A speedometer measures the instantaneous speed of a vehicle. An odometer measures total distance, a barometer measures air pressure, and a thermometer measures temperature. The speedometer is the correct device.
Q48. On a distance-time graph, the steeper the line, the:
A steeper slope means more distance is covered in the same time, so the speed is faster. A less steep slope means slower speed. Rest is horizontal. The steepness indicates the speed.
Q49. A bicycle moves with a speed of 5 metre per second. How much time will it take to cover 1 kilometre?
1 km = 1000 m. Time = Distance ÷ Speed = 1000 m ÷ 5 m/s = 200 seconds. 0.005 s is 5/1000, 5000 s is 1000×5, and 5 s is for 25 m. The correct answer is 200 seconds.
Q50. A swinging child on a swing completes 15 oscillations in 30 second. The time period is:
Time period = Total time ÷ Number of oscillations = 30 s ÷ 15 = 2 seconds. 0.5 s is 15/30, 15 s is the number, and 450 s is 30×15. The correct answer is 2 seconds.